Mean
A=[1 2 3 4;5 6 7 8];
i)
mean (A)=mean(A,1)=[3,4,5,6]; %column-wise mean
Explanation:
1 2 3 4
5 6 7 8
---------
3 4 5 6
5 6 7 8
---------
3 4 5 6
ii)
mean(A,2)= [2.5,4.5];
1 2 3 4-----(1+2+3+4)/4 = 10/4 =2.5
5 6 7 8-----(5+6+7+8)/4 = 26/4 =4.5
5 6 7 8-----(5+6+7+8)/4 = 26/4 =4.5
Size
size(A,2) = 4 %number of columns
size(A,1) = 2%number of rows
We Normalize images to reduce the
error due to lighting conditions
A=
1 2 3 4
5 6 7 8
A'=
1 5
2 6
3 7
4 8
temp=A'(:);
=
1
2
3
4
5
6
7
8
A=
1 2 3 4
5 6 7 8
A'=
1 5
2 6
3 7
4 8
temp=A'(:);
=
1
2
3
4
5
6
7
8
If A=
1 2
3 4
-----
2 3
1 2
3 4
-----
2 3
here n-1=
2-1=1;
std(A)=
[√ (1-2)2+(3-2)2/(2-1) √ (2-3)2+(4-3)2
/(2-1) ] =[ √2/1 √2/1] =
[√2 √2]= [1.414 1.414];
Sum(A,1)=sum(A)=[4 6]
Sum(A,2)=[3 7]%row wise sum
A(:,1).^2
=
1
9
A= 1 B= 4
2 5
2 5
3 6
A’*B =32
[1 2 3]* 4
4+
5
= 10
6 18
-------
32
img=uint8(image); %converts to unsigned 8-bit
integer. Values range from 0 to 255
Normalize cheyataniki
its own mean tho minus chestamu
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